Column $(I)$ contains products and Column $(II)$ contains the processes to prepare them. Match the processes in Column $(II)$ with the products in Column $(I)$.
Column - $(I)$ Product Column - $(II)$ Preparation Process $(A)$ Butan$-1-$ol $(i)$ Hydration of propene in the presence of dilute sulfuric acid $(B)$ Propan$-2-$ol $(ii)$ Reaction of propanone with methylmagnesium bromide followed by hydrolysis $(C)$ $2-$Methylpropan$-2-$ol $(iii)$ Hydroboration of propene followed by reaction with $(NaOH + H_2O_2)$ $(D)$ Propan$-1-$ol $(iv)$ Catalytic reduction of butanal
| Column - $(I)$ Product | Column - $(II)$ Preparation Process |
| $(A)$ Butan$-1-$ol | $(i)$ Hydration of propene in the presence of dilute sulfuric acid |
| $(B)$ Propan$-2-$ol | $(ii)$ Reaction of propanone with methylmagnesium bromide followed by hydrolysis |
| $(C)$ $2-$Methylpropan$-2-$ol | $(iii)$ Hydroboration of propene followed by reaction with $(NaOH + H_2O_2)$ |
| $(D)$ Propan$-1-$ol | $(iv)$ Catalytic reduction of butanal |
(A) $(A$ $\rightarrow iv), (B$ $\rightarrow i), (C$ $\rightarrow ii), (D$ $\rightarrow iii)$
$(A)$ Butan$-1-$ol is prepared by the catalytic reduction of butanal $(CH_3CH_2CH_2CHO + H_2 \rightarrow CH_3CH_2CH_2CH_2OH)$.
$(B)$ Propan$-2-$ol is prepared by the hydration of propene in the presence of dilute sulfuric acid (Markovnikov addition).
$(C)$ $2-$Methylpropan$-2-$ol is prepared by the reaction of propanone with methylmagnesium bromide (Grignard reagent) followed by hydrolysis.
$(D)$ Propan$-1-$ol is prepared by the hydroboration-oxidation of propene (Anti-Markovnikov addition).
$(A)$ Butan$-1-$ol is prepared by the catalytic reduction of butanal $(CH_3CH_2CH_2CHO + H_2 \rightarrow CH_3CH_2CH_2CH_2OH)$.
$(B)$ Propan$-2-$ol is prepared by the hydration of propene in the presence of dilute sulfuric acid (Markovnikov addition).
$(C)$ $2-$Methylpropan$-2-$ol is prepared by the reaction of propanone with methylmagnesium bromide (Grignard reagent) followed by hydrolysis.
$(D)$ Propan$-1-$ol is prepared by the hydroboration-oxidation of propene (Anti-Markovnikov addition).
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Similar Questions
Match the chemical conversions in List-$I$ with the appropriate reagents in List-$II$ and select the correct answer using the code given below the lists:
List-$I$:
$P$. $tert$-butyl chloride $\rightarrow$ isobutylene
$Q$. Sodium $tert$-butoxide $\rightarrow$ $tert$-butyl ethyl ether
$R$. $1$-methylcyclopentene $\rightarrow$ $1$-methylcyclopentanol
$S$. $1$-methylcyclopentene $\rightarrow$ $2$-methylcyclopentanol (trans-isomer)
List-$II$:
$1$. $(i) \ Hg(OAc)_2; (ii) \ NaBH_4$
$2$. $NaOEt$
$3$. $EtBr$
$4$. $(i) \ BH_3; (ii) \ H_2O_2/NaOH$
Codes: $P \quad Q \quad R \quad S$
List-$I$:
$P$. $tert$-butyl chloride $\rightarrow$ isobutylene
$Q$. Sodium $tert$-butoxide $\rightarrow$ $tert$-butyl ethyl ether
$R$. $1$-methylcyclopentene $\rightarrow$ $1$-methylcyclopentanol
$S$. $1$-methylcyclopentene $\rightarrow$ $2$-methylcyclopentanol (trans-isomer)
List-$II$:
$1$. $(i) \ Hg(OAc)_2; (ii) \ NaBH_4$
$2$. $NaOEt$
$3$. $EtBr$
$4$. $(i) \ BH_3; (ii) \ H_2O_2/NaOH$
Codes: $P \quad Q \quad R \quad S$
DifficultIIT 2013
View SolutionWhich of the following reactions will yield $2-propanol$? Select the correct answer from $a, b, c$ and $d$.
$I. \, CH_2 = CH - CH_3 + H_2O \xrightarrow{H^+} $
$II. \, CH_3 - CHO \xrightarrow[(ii) \, H_2O]{(i) \, CH_3MgI} $
$III. \, CH_2O \xrightarrow[(ii) \, H_2O]{(i) \, C_2H_5MgI} $
$IV. \, CH_2 = CH - CH_3 \xrightarrow{KMnO_4} $
$I. \, CH_2 = CH - CH_3 + H_2O \xrightarrow{H^+} $
$II. \, CH_3 - CHO \xrightarrow[(ii) \, H_2O]{(i) \, CH_3MgI} $
$III. \, CH_2O \xrightarrow[(ii) \, H_2O]{(i) \, C_2H_5MgI} $
$IV. \, CH_2 = CH - CH_3 \xrightarrow{KMnO_4} $
Medium
View SolutionIn the following reaction,$\text{Phenol}$ $\xrightarrow{Zn \, \text{dust}} x$ $\xrightarrow[\text{Anhy.} \, ZnCl_2]{CH_3Cl} y$ $\xrightarrow{\text{Alk.} \, KMnO_4} z$. The product $z$ is:
Medium
View SolutionBased on the provided reaction scheme,determine the total number of stereoisomers of $B$.
Which of the following statements is not correct?
Difficult
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