Match Column-$I$ with Column-$II$.
Column-$I$ Column-$II$ $(1)$ Angle of projection for a projectile launched horizontally with constant speed $(a)$ $0$ $(2)$ Horizontal component of acceleration for a projectile launched horizontally with constant speed $(b)$ $0^o$
| Column-$I$ | Column-$II$ |
| $(1)$ Angle of projection for a projectile launched horizontally with constant speed | $(a)$ $0$ |
| $(2)$ Horizontal component of acceleration for a projectile launched horizontally with constant speed | $(b)$ $0^o$ |
(A) For a projectile launched horizontally,the initial velocity vector is parallel to the ground,so the angle of projection $\theta = 0^o$. Thus,$(1)$ matches with $(b)$.
In projectile motion,the only acceleration acting on the object is the acceleration due to gravity $(g)$,which acts vertically downwards. Therefore,the horizontal component of acceleration is $0$. Thus,$(2)$ matches with $(a)$.
The correct matching is $(1-b, 2-a)$.
In projectile motion,the only acceleration acting on the object is the acceleration due to gravity $(g)$,which acts vertically downwards. Therefore,the horizontal component of acceleration is $0$. Thus,$(2)$ matches with $(a)$.
The correct matching is $(1-b, 2-a)$.
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