The unit of the spring constant is $J\,m^{-2}$. Is this statement true or false? If false,correct it.
(A) The statement is true.
The potential energy $U$ of a spring is given by $U = \frac{1}{2} k x^2$,where $k$ is the spring constant and $x$ is the displacement.
Rearranging for $k$,we get $k = \frac{2U}{x^2}$.
The unit of energy $U$ is Joule $(J)$ and the unit of displacement $x$ is meter $(m)$.
Therefore,the unit of $k$ is $\frac{J}{m^2} = J\,m^{-2}$.
The potential energy $U$ of a spring is given by $U = \frac{1}{2} k x^2$,where $k$ is the spring constant and $x$ is the displacement.
Rearranging for $k$,we get $k = \frac{2U}{x^2}$.
The unit of energy $U$ is Joule $(J)$ and the unit of displacement $x$ is meter $(m)$.
Therefore,the unit of $k$ is $\frac{J}{m^2} = J\,m^{-2}$.
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