Although the units of torque and work are the same,why are they not the same physical quantities?
(N/A) The unit of both torque and work is $N \cdot m$ (Newton-meter) or $J$ (Joule). However,they are different physical quantities because:
$1$. Torque is a vector quantity,whereas work is a scalar quantity.
$2$. Torque represents the rotational effect of a force (turning effect),while work represents the energy transferred by a force acting over a displacement.
$1$. Torque is a vector quantity,whereas work is a scalar quantity.
$2$. Torque represents the rotational effect of a force (turning effect),while work represents the energy transferred by a force acting over a displacement.
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Similar Questions
The dimensions of angular momentum,latent heat,and capacitance are,respectively:
DifficultJEE MAIN 2013
View SolutionMatch List-$I$ with List-$II$.
List-$I$ List-$II$ $(A)$ Torque $(I)$ $Nms^{-1}$ $(B)$ Stress $(II)$ $Jkg^{-1}$ $(C)$ Latent Heat $(III)$ $Nm$ $(D)$ Power $(IV)$ $Nm^{-2}$
Choose the correct answer from the options below.
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ Torque | $(I)$ $Nms^{-1}$ |
| $(B)$ Stress | $(II)$ $Jkg^{-1}$ |
| $(C)$ Latent Heat | $(III)$ $Nm$ |
| $(D)$ Power | $(IV)$ $Nm^{-2}$ |
Choose the correct answer from the options below.
Which quantity among the following has neither units nor dimensions?
Names of units of some physical quantities are given in List-$I$ and their dimensional formulae are given in List-$II$. Match the correct pairs in the lists:
$A$. $Pa \cdot s$ $(i)$. $[L^2 T^{-2} K^{-1}]$ $B$. $N \cdot m \cdot K^{-1}$ $(ii)$. $[MLT^{-3} K^{-1}]$ $C$. $J \cdot kg^{-1} \cdot K^{-1}$ $(iii)$. $[ML^{-1} T^{-1}]$ $D$. $W \cdot m^{-1} \cdot K^{-1}$ $(iv)$. $[ML^2 T^{-2} K^{-1}]$
| $A$. $Pa \cdot s$ | $(i)$. $[L^2 T^{-2} K^{-1}]$ |
| $B$. $N \cdot m \cdot K^{-1}$ | $(ii)$. $[MLT^{-3} K^{-1}]$ |
| $C$. $J \cdot kg^{-1} \cdot K^{-1}$ | $(iii)$. $[ML^{-1} T^{-1}]$ |
| $D$. $W \cdot m^{-1} \cdot K^{-1}$ | $(iv)$. $[ML^2 T^{-2} K^{-1}]$ |
DifficultTS EAMCET 2005
View SolutionThe ratio $\left(\frac{E}{W}\right)$ of relative strength of electromagnetic force $(E)$ to weak nuclear force $(W)$ is,
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