Evaluate the following exponential numbers:
$(i)$ Add $8.56 \times 10^{6}$ and $10.64 \times 10^{5}$.
$(ii)$ Subtract $5.80 \times 10^{-4}$ from $3.33 \times 10^{-3}$.
$(i)$ Add $8.56 \times 10^{6}$ and $10.64 \times 10^{5}$.
$(ii)$ Subtract $5.80 \times 10^{-4}$ from $3.33 \times 10^{-3}$.
$(i)$ To add the numbers,make the exponents the same:
$8.56 \times 10^{6} + 1.064 \times 10^{6} = (8.56 + 1.064) \times 10^{6} = 9.624 \times 10^{6}$
$(ii)$ To subtract the numbers,make the exponents the same:
$3.33 \times 10^{-3} - 0.58 \times 10^{-3} = (3.33 - 0.58) \times 10^{-3} = 2.75 \times 10^{-3}$
$8.56 \times 10^{6} + 1.064 \times 10^{6} = (8.56 + 1.064) \times 10^{6} = 9.624 \times 10^{6}$
$(ii)$ To subtract the numbers,make the exponents the same:
$3.33 \times 10^{-3} - 0.58 \times 10^{-3} = (3.33 - 0.58) \times 10^{-3} = 2.75 \times 10^{-3}$
Explore More
Similar Questions
The order of energy equivalent to $1 \ erg$,$1 \ joule$,and $1 \ calorie$ is:
Easy
View SolutionThe mass of a coin Manoj has is $4 \ g$ and its volume is $2 \ cm^3$. What will be the density of the substance in $SI$ units?
Easy
View SolutionThe number of significant figures in $6.0023$ are
Easy
View SolutionRound up the following numbers to three significant figures:
$(i)$ $34.216$
$(ii)$ $10.4107$
$(iii)$ $0.04597$
$(iv)$ $2808$
$(i)$ $34.216$
$(ii)$ $10.4107$
$(iii)$ $0.04597$
$(iv)$ $2808$
Medium
View SolutionWhat do you mean by significant figures?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo