Provide the four quantum numbers for the two | vedclass

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Question

(A) The electronic configuration of $Ca$ $(Z = 20)$ is $[Ar]^{18} 4s^2$.The two outermost electrons are in the $4s$ orbital.For the $4s$ orbital,the p

Vedclass · Accepted Answer

$n=4, l=0, m_l=0, m_s=+1/2$ and $n=4, l=0, m_l=0, m_s=-1/2$

Vedclass · Answer

(A) The electronic configuration of $Ca$ $(Z = 20)$ is $[Ar]^{18} 4s^2$.The two outermost electrons are in the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n = 4$ and the azimuthal quantum number $l = 0$.Since $l = 0$,the magnetic quantum number $m_l = 0$.The spin quantum numbers for the two electrons are $m_s = +1/2$ and $m_s = -1/2$.Thus,the four quantum numbers are $(4, 0, 0, +1/2)$ and $(4, 0, 0, -1/2)$.

List-$A$	List-$B$
$(1)$ Principal quantum number	$(A)$ Shape of the orbital
$(2)$ Azimuthal quantum number	$(B)$ Spin of the electron
$(3)$ Magnetic quantum number	$(C)$ Orientation of the orbital in space
$(4)$ Spin quantum number	$(D)$ Size of the orbital

Provide the four quantum numbers for the two outermost electrons of $Ca$ $(Z = 20)$.

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