If the outermost electrons of an element are represented as $(a)$ $3s^1$,$(b)$ $2p^3$,and $(c)$ $3p^5$,what will be the atomic numbers of these elements?

(N/A) For the outermost configuration $3s^1$,the complete electronic configuration is $1s^2 2s^2 2p^6 3s^1$. The total number of electrons is $2+2+6+1 = 11$. Thus,the atomic number $Z = 11$.
$(b)$ For the outermost configuration $2p^3$,the complete electronic configuration is $1s^2 2s^2 2p^3$. The total number of electrons is $2+2+3 = 7$. Thus,the atomic number $Z = 7$.
$(c)$ For the outermost configuration $3p^5$,the complete electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^5$. The total number of electrons is $2+2+6+2+5 = 17$. Thus,the atomic number $Z = 17$.