XeF_2 molecule is | vedclass

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(D) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ sigma bonds with $F$ atoms and has $3$ lone pairs.The steric number is $

Vedclass · Accepted Answer

Linear

Vedclass · Answer

(D) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ sigma bonds with $F$ atoms and has $3$ lone pairs.The steric number is $2 + 3 = 5$,which corresponds to $sp^3d$ hybridization.According to $VSEPR$ theory,the $3$ lone pairs occupy the equatorial positions of the trigonal bipyramidal geometry to minimize repulsion.Therefore,the molecule adopts a linear shape.

$XeF_2$ molecule is

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