What is the correct order of electron pair repulsion strength in a covalent molecule according to $VSEPR$ theory?
- A$lone \ pair - lone \ pair > lone \ pair - bond \ pair > bond \ pair - bond \ pair$
- B$bond \ pair - bond \ pair > lone \ pair - bond \ pair > lone \ pair - lone \ pair$
- C$lone \ pair - lone \ pair > bond \ pair - bond \ pair > lone \ pair - bond \ pair$
- D$lone \ pair - bond \ pair > lone \ pair - lone \ pair > bond \ pair - bond \ pair$
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Similar Questions
The shape of $O_2F_2$ is similar to that of:
Medium
View SolutionBased on the $VSEPR$ model,match the xenon compounds given in List-$I$ with the corresponding geometries and the number of lone pairs on xenon given in List-$II$ and choose the correct option.
List-$I$ List-$II$ $(P)$ $XeF_2$ $(5)$ Trigonal bipyramidal and three lone pairs of electrons $(Q)$ $XeF_4$ $(3)$ Square planar and two lone pairs of electrons $(R)$ $XeO_3$ $(2)$ Pyramidal and one lone pair of electrons $(S)$ $XeO_3F_2$ $(4)$ Trigonal bipyramidal and no lone pairs of electrons
| List-$I$ | List-$II$ |
|---|---|
| $(P)$ $XeF_2$ | $(5)$ Trigonal bipyramidal and three lone pairs of electrons |
| $(Q)$ $XeF_4$ | $(3)$ Square planar and two lone pairs of electrons |
| $(R)$ $XeO_3$ | $(2)$ Pyramidal and one lone pair of electrons |
| $(S)$ $XeO_3F_2$ | $(4)$ Trigonal bipyramidal and no lone pairs of electrons |
Which of the following has the smallest bond angle?
Medium
View SolutionMatch the molecules in List-$I$ with their respective shapes in List-$II$.
List-$I$ (Molecule) List-$II$ (Shape) $A. SF_4$ $I. T\text{-shaped}$ $B. ClF_3$ $II. \text{Square planar}$ $C. BrF_5$ $III. \text{See-saw}$ $D. XeF_4$ $IV. \text{Square pyramidal}$
| List-$I$ (Molecule) | List-$II$ (Shape) |
|---|---|
| $A. SF_4$ | $I. T\text{-shaped}$ |
| $B. ClF_3$ | $II. \text{Square planar}$ |
| $C. BrF_5$ | $III. \text{See-saw}$ |
| $D. XeF_4$ | $IV. \text{Square pyramidal}$ |
What is the bond angle of $H-O-H$ in $H_2O$ (in $^\circ$)?
Easy
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