Why is the bond angle in $CH_4$ not $90^{\circ}$,even though the outermost $p$-orbitals of carbon are at $90^{\circ}$ to each other?
- ADue to $sp$ hybridization
- BDue to $sp^2$ hybridization
- CDue to $sp^3$ hybridization
- DDue to $dsp^2$ hybridization
Explore More
Similar Questions
What is the bond angle $\angle F-B-F$ in $BF_3$ (in $^{\circ}$)?
Identify the molecules which have $sp$-hybridised carbon$(s)$ from the list given below:
$I$. Ethane nitrile $(CH_3CN)$
$II$. Buta$-1,3-$diene $(CH_2=CH-CH=CH_2)$
$III$. Propan$-1,2-$diene $(CH_2=C=CH_2)$
$IV$. Ethyne $(HC \equiv CH)$
$V$. Benzene $(C_6H_6)$
$I$. Ethane nitrile $(CH_3CN)$
$II$. Buta$-1,3-$diene $(CH_2=CH-CH=CH_2)$
$III$. Propan$-1,2-$diene $(CH_2=C=CH_2)$
$IV$. Ethyne $(HC \equiv CH)$
$V$. Benzene $(C_6H_6)$
What is the $CORRECT$ geometry and hybridisation for $SF_4$?
Medium
View SolutionConsider $PF_{5}$,$BrF_{5}$,$PCl_{3}$,$SF_{6}$,$[ICl_{4}]^{-}$,$ClF_{3}$ and $IF_{5}$.
Amongst the above molecule$(s)$/ion$(s)$,the number of molecule$(s)$/ion$(s)$ having $sp^{3}d^{2}$ hybridisation is $........$
Amongst the above molecule$(s)$/ion$(s)$,the number of molecule$(s)$/ion$(s)$ having $sp^{3}d^{2}$ hybridisation is $........$
DifficultJEE MAIN 2022
View SolutionWhich of the following is a linear molecule?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo