Determine the number of $\sigma$ and $\pi$ bonds in the following molecules:
$(i)$ $O_2$
$(ii)$ $N_2$
$(iii)$ $C_6H_6$ (Benzene)
$(iv)$ $O_3$ (Ozone)

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The number of $\sigma$ and $\pi$ bonds are calculated as follows:
$(i)$ $O_2$ $(O=O)$: $1 \sigma, 1 \pi$.
$(ii)$ $N_2$ $(N\equiv N)$: $1 \sigma, 2 \pi$.
$(iii)$ $C_6H_6$ (Benzene): It has $12 \sigma$ bonds ($6$ $C-C$ and $6$ $C-H$) and $3 \pi$ bonds.
$(iv)$ $O_3$ (Ozone): The resonance structure shows $2 \sigma$ bonds and $1 \pi$ bond (delocalized over the structure).

Explore More

Similar Questions

Which overlap results in the formation of the strongest bond?

The strongest bond is formed when atomic orbitals undergo:

What is the total number of sigma $(\sigma)$ and pi $(\pi)$ bonds in the following molecules?
$(a)$ $C_{2}H_{2}$
$(b)$ $C_{2}H_{4}$

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: Zero orbital overlap is an out-of-phase overlap.
Reason $R$: It results due to different orientation/direction of approach of orbitals.
In the light of the above statements,choose the correct answer from the options given below.

$A$ carbon-carbon triple bond in ethyne $(HC \equiv CH)$ consists of:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo