Identify the conjugate base of {H_2}PO_3^- an | vedclass

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Question

(A) The conjugate base of an acid is formed by removing one proton $({H^+})$ from the species. For ${H_2}PO_3^-$,removing one ${H^+}$ gives ${HPO_3^{2

Vedclass · Accepted Answer

Conjugate base: ${HPO_3^{2-}}$; Conjugate acid: ${H_2CO_3}$

Vedclass · Answer

(A) The conjugate base of an acid is formed by removing one proton $({H^+})$ from the species. For ${H_2}PO_3^-$,removing one ${H^+}$ gives ${HPO_3^{2-}}$. The conjugate acid of a base is formed by adding one proton $({H^+})$ to the species. For ${HCO_3^-}$,adding one ${H^+}$ gives ${H_2CO_3}$. Therefore,the conjugate base is ${HPO_3^{2-}}$ and the conjugate acid is ${H_2CO_3}$.

Identify the conjugate base of ${H_2}PO_3^-$ and the conjugate acid of ${HCO_3^-}$.

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