$7.5 \ A$ current is passed for $200 \ s$ through $AgNO_3$ solution. If experimentally $1.08 \ g$ of $Ag$ is obtained,then calculate the current efficiency (cell capacity). $[Ag = 108 \ u]$

(N/A) The theoretical amount of $Ag$ deposited is calculated using Faraday's first law of electrolysis: $w = \frac{M \times I \times t}{n \times F}$.
Here,$M = 108 \ g/mol$,$I = 7.5 \ A$,$t = 200 \ s$,$n = 1$,and $F = 96500 \ C/mol$.
$w_{theoretical} = \frac{108 \times 7.5 \times 200}{1 \times 96500} = \frac{162000}{96500} \approx 1.6788 \ g$.
The current efficiency is given by $\frac{w_{experimental}}{w_{theoretical}} \times 100$.
Efficiency $= \frac{1.08}{1.6788} \times 100 \approx 64.33 \ \%$.