Match the $CH_{3}X$ compounds in Column-$(I)$ with their $C-X$ bond length in Column-$(II)$ and dipole moment in Column-$(III)$.

$(I)$ Compound	$(II)$ $C-X$ Bond Length $(pm)$	$(III)$ Dipole Moment $(D)$
$(A)$ $H_3C-F$	$(i)$ $214$	$(1)$ $1.636$
$(B)$ $H_3C-Cl$	$(ii)$ $193$	$(2)$ $1.830$
$(C)$ $H_3C-Br$	$(iii)$ $178$	$(3)$ $1.847$
$(D)$ $H_3C-I$	$(iv)$ $139$	$(4)$ $1.860$

(A) The bond length increases as the size of the halogen atom increases: $C-I > C-Br > C-Cl > C-F$. Thus, $(A-iv, B-iii, C-ii, D-i)$.
For dipole moment, the order is $CH_3Cl > CH_3F > CH_3Br > CH_3I$ due to the balance between electronegativity and bond length. The values are: $CH_3Cl (1.860 \ D)$, $CH_3F (1.847 \ D)$, $CH_3Br (1.830 \ D)$, $CH_3I (1.636 \ D)$.
Matching the values: $(A-4, B-1, C-2, D-3)$.
Correct matching: $(A-iv, 4; B-iii, 1; C-ii, 2; D-i, 3)$.