Match the reactants in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Products) $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ $i$. $CH_3CH_2CH_2Br$ $B$. $CH_3CH=CH_2 + HI \rightarrow$ $ii$. $BrCH_2-CH_2Br$ $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ $iii$. $CH_3CHICH_3$ $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ $iv$. $C_6H_5I$
| Column-$I$ (Reactants) | Column-$II$ (Products) |
| $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ | $i$. $CH_3CH_2CH_2Br$ |
| $B$. $CH_3CH=CH_2 + HI \rightarrow$ | $ii$. $BrCH_2-CH_2Br$ |
| $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ | $iii$. $CH_3CHICH_3$ |
| $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ | $iv$. $C_6H_5I$ |
(A-II, B-III, C-IV, D-I) The reactions are matched as follows:
$A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4} BrCH_2-CH_2Br$ (Vicinal dihalide formation) $\rightarrow ii$
$B$. $CH_3CH=CH_2 + HI \rightarrow CH_3CHICH_3$ (Markovnikov addition) $\rightarrow iii$
$C$. $C_6H_5N_2^+X^- + KI \rightarrow C_6H_5I + N_2 + KX$ (Sandmeyer-type reaction) $\rightarrow iv$
$D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide} CH_3CH_2CH_2Br$ (Anti-Markovnikov addition) $\rightarrow i$
Therefore,the correct matching is: $A-ii, B-iii, C-iv, D-i$.
$A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4} BrCH_2-CH_2Br$ (Vicinal dihalide formation) $\rightarrow ii$
$B$. $CH_3CH=CH_2 + HI \rightarrow CH_3CHICH_3$ (Markovnikov addition) $\rightarrow iii$
$C$. $C_6H_5N_2^+X^- + KI \rightarrow C_6H_5I + N_2 + KX$ (Sandmeyer-type reaction) $\rightarrow iv$
$D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide} CH_3CH_2CH_2Br$ (Anti-Markovnikov addition) $\rightarrow i$
Therefore,the correct matching is: $A-ii, B-iii, C-iv, D-i$.
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