$15 \ mL$ of $N/10$ $NaOH$ solution completely neutralizes $12 \ mL$ of $H_2SO_4$ solution. The normality of $H_2SO_4$ solution will be:

  • A
    $N/5$
  • B
    $N/10$
  • C
    $N/8$
  • D
    $N$

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