2 N - HCl will have the same molar concentra | vedclass

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(D) The relationship between Normality $(N)$ and Molarity $(M)$ is given by: $N = M 	imes 	ext{n-factor}$.For $HCl$,the n-factor is $1$,so $2 \ N -

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$4$

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(D) The relationship between Normality $(N)$ and Molarity $(M)$ is given by: $N = M 	imes 	ext{n-factor}$.For $HCl$,the n-factor is $1$,so $2 \ N - HCl = 2 \ M - HCl$.For $H_2SO_4$,the n-factor is $2$ (since it is a dibasic acid).To have the same molar concentration $(2 \ M)$,the Normality of $H_2SO_4$ must be: $N = 2 \ M 	imes 2 = 4 \ N$.Therefore,$2 \ N - HCl$ has the same molar concentration as $4 \ N - H_2SO_4$.

$2 \ N - HCl$ will have the same molar concentration as $....... \ N - H_2SO_4$

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