Match the reaction in Column-$I$ with the mechanism in Column-$II$.
Column-$I$ (Reaction)Column-$II$ (Mechanism)
$A$. $CH_3OCH_2CH_3 + HI \to CH_3I + CH_3CH_2OH$$i$. $S_{E}2$ Aromatic
$B$. $(CH_3)_3COCH_3 + HI \to CH_3OH + (CH_3)_3CI$$ii$. $S_{N}1$
$C$. $C_6H_5OCH_3 + Br_2(CH_3COOH) \to p$-Bromoanisole$iii$. Elimination $(\beta)$
$D$. $CH_3CH_2OH + H_2SO_4 (443 \ K) \to CH_2=CH_2$$iv$. $S_{N}2$

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(A-IV, B-II, C-I, D-III) The correct matches are as follows:
$A \to iv$: The reaction of primary alkyl ethers with $HI$ proceeds via an $S_{N}2$ mechanism.
$B \to ii$: The reaction of ethers containing a tertiary alkyl group with $HI$ proceeds via an $S_{N}1$ mechanism because a stable carbocation is formed.
$C \to i$: The bromination of anisole is an electrophilic aromatic substitution ($S_{E}2$ Aromatic) reaction.
$D \to iii$: The dehydration of ethanol to ethene in the presence of concentrated $H_2SO_4$ at $443 \ K$ is a $\beta$-elimination reaction.
Therefore,the correct sequence is: $A-iv, B-ii, C-i, D-iii$.

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Arrange the following compounds in the increasing order of polarity:
$A. CH_3CH_2OCH_2CH_3$
$B. CH_3CH_2OH$
$C. CH_3COCH_3$
$D. CH_3COOH$
Choose the correct answer from the options given below:

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