$60 \ g$ of a compound on analysis gave $C = 24 \ g$,$H = 4 \ g$ and $O = 32 \ g$. Its empirical formula is

$0.833 \, \text{mol}$ of a hydrocarbon contains $10 \, \text{g}$ of hydrogen. If the empirical formula of the compound is $CH_2O$,determine its molecular formula.

The formula for calcium chlorite is

$1.25 \ g$ of a metal $(M)$ reacts with oxygen completely to produce $1.68 \ g$ of metal oxide. The empirical formula of the metal oxide is
[molar mass of $M$ and $O$ are $69.7 \ g \ mol^{-1}$ and $16.0 \ g \ mol^{-1}$,respectively]

$0.5 \ g$ of hydrocarbon gave $0.9 \ g$ of water on combustion. The percentage of carbon in the hydrocarbon is:

An organic compound contains $49.3\%$ carbon,$6.84\%$ hydrogen,and the rest is oxygen. Its vapor density is $73$. What is its molecular formula?