$0.2595 \ g$ of an organic substance in a quantitative analysis yielded $0.35 \ g$ of barium sulphate. The percentage of sulphur in the substance is $...$

In the Kjeldahl's method for estimation of nitrogen present in a soil sample,ammonia evolved from $0.75 \ g$ of sample neutralized $10 \ mL$ of $1 \ M \ H_2SO_4$. The percentage of nitrogen in the soil is (in $.33$)

Differentiate between the principle of estimation of nitrogen in an organic compound by $(i)$ Dumas method and $(ii)$ Kjeldahl's method.

$0.1 \ g$ of an organic compound was analyzed by the Kjeldahl method. The $NH_3$ produced was absorbed in $30 \ mL$ of $N/5$ $H_2SO_4$. The remaining acid required $20 \ mL$ of $N/10$ $NaOH$ for neutralization. Calculate the percentage of nitrogen in the organic compound.

During $S$ estimation,$160 \ mg$ of an organic compound gives $466 \ mg$ of barium sulphate. The percentage of Sulphur in the given compound is . . . . . . $\%.$ (Given molar mass in $g \ mol^{-1}$ of $Ba: 137, S: 32, O: 16$)

Calculate the percentage of nitrogen in $0.25 \ g$ of an organic compound if $38 \ cm^3$ of $N_2$ gas is evolved at $300 \ K$ and $96 \ kPa$ pressure. (Given: $1 \ atm = 101.3 \ kPa$)