19 persons went to a hotel for a combined din | vedclass

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Question

(D) Let the average expenditure of all $19$ persons be $x$.Total expenditure of $19$ persons $= 19x$.Expenditure of $13$ persons $= 13 	imes 79 = 102

Vedclass · Accepted Answer

$1536.07$

Vedclass · Answer

(D) Let the average expenditure of all $19$ persons be $x$.Total expenditure of $19$ persons $= 19x$.Expenditure of $13$ persons $= 13 	imes 79 = 1027$.Remaining persons $= 19 - 13 = 6$.Expenditure of each of the remaining $6$ persons $= x + 4$.Total expenditure of these $6$ persons $= 6(x + 4) = 6x + 24$.According to the problem:$1027 + 6x + 24 = 19x$$1051 = 19x - 6x$$1051 = 13x$$x = \frac{1051}{13} \approx 80.846$.Total expenditure $= 19x = 19 	imes \frac{1051}{13} = \frac{19969}{13} \approx 1536.077$.Rounding to two decimal places,the total money spent is $Rs. 1536.07$.

$19$ persons went to a hotel for a combined dinner party. $13$ of them spent $Rs. 79$ each on their dinner and the rest spent $Rs. 4$ more than the average expenditure of all the $19$ persons. What was the total money spent by them?

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