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(A) $1$. $10$ years ago,the average age of $25$ teachers was $45$ years. So,the total age was $25 	imes 45 = 1125$ years.$2$. $4$ years ago (i.e.,$6$

Vedclass · Accepted Answer

$54 \frac{18}{25}$ years

Vedclass · Answer

(A) $1$. $10$ years ago,the average age of $25$ teachers was $45$ years. So,the total age was $25 	imes 45 = 1125$ years.$2$. $4$ years ago (i.e.,$6$ years after the initial point),the total age of these $25$ teachers was $1125 + (6 	imes 25) = 1125 + 150 = 1275$ years.$3$. When the principal retired at $60$ years,the total age of the remaining $24$ teachers was $1275 - 60 = 1215$ years.$4$. One year later (i.e.,$3$ years ago from the present),the total age of the $24$ teachers was $1215 + (1 	imes 24) = 1239$ years.$5$. $A$ new principal aged $54$ years was recruited,so the total age of the $25$ staff members became $1239 + 54 = 1293$ years.$6$. At the present time ($3$ years later),the total age of all $25$ staff members is $1293 + (3 	imes 25) = 1293 + 75 = 1368$ years.$7$. The present average age is $\frac{1368}{25} = 54 \frac{18}{25}$ years.

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