If frac{5a+3b}{2a-3b} = frac{23}{5},then the | vedclass

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(D) Given equation: $\frac{5a+3b}{2a-3b} = \frac{23}{5}$Divide the numerator and denominator of the left side by $b$:$\frac{5(a/b) + 3}{2(a/b) - 3} =

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$4:1$

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(D) Given equation: $\frac{5a+3b}{2a-3b} = \frac{23}{5}$Divide the numerator and denominator of the left side by $b$:$\frac{5(a/b) + 3}{2(a/b) - 3} = \frac{23}{5}$Let $\frac{a}{b} = x$. Substituting this into the equation:$\frac{5x + 3}{2x - 3} = \frac{23}{5}$Cross-multiply to solve for $x$:$5(5x + 3) = 23(2x - 3)$$25x + 15 = 46x - 69$Rearrange the terms:$69 + 15 = 46x - 25x$$84 = 21x$$x = \frac{84}{21} = 4$Since $x = \frac{a}{b} = 4$,the ratio $a:b$ is $4:1$.

If $\frac{5a+3b}{2a-3b} = \frac{23}{5}$,then the value of $a:b$ is:

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