A, B and C can do a piece of work individuall | vedclass

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(D) $(A + B)$'s $2$ days' work $= 2 	imes (\frac{1}{8} + \frac{1}{10}) = 2 	imes \frac{5+4}{40} = 2 	imes \frac{9}{40} = \frac{9}{20}$.Remaining wo

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$\frac{53}{10}$

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(D) $(A + B)$'s $2$ days' work $= 2 	imes (\frac{1}{8} + \frac{1}{10}) = 2 	imes \frac{5+4}{40} = 2 	imes \frac{9}{40} = \frac{9}{20}$.Remaining work $= 1 - \frac{9}{20} = \frac{11}{20}$.$(B + C)$'s $1$ day's work $= \frac{1}{10} + \frac{1}{15} = \frac{3+2}{30} = \frac{5}{30} = \frac{1}{6}$.Days taken by $B$ and $C$ to complete the remaining work $= \frac{	ext{Remaining work}}{	ext{Efficiency of } (B+C)} = \frac{11/20}{1/6} = \frac{11}{20} 	imes 6 = \frac{33}{10}$ days.Total days to complete the work $= 2 + \frac{33}{10} = \frac{20+33}{10} = \frac{53}{10}$ days.

$A, B$ and $C$ can do a piece of work individually in $8, 10$ and $15$ days respectively. $A$ and $B$ start working,but $A$ quits after working for $2$ days. After this,$C$ joins $B$ until the completion of the work. In how many days will the work be completed?

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