(A) The formula for work completion is $M_1 \times D_1 \times H_1 = M_2 \times D_2 \times H_2$, where $M$ is the number of men, $D$ is the number of d

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(A) The formula for work completion is $M_1 \times D_1 \times H_1 = M_2 \times D_2 \times H_2$, where $M$ is the number of men, $D$ is the number of days, and $H$ is the number of hours per day.Given:$M_1 = 10, D_1 = 18, H_1 = 6$$M_2 = 15, D_2 = 12, H_2 = ?$Substituting the values into the formula:$10 \times 18 \times 6 = 15 \times 12 \times H_2$$1080 = 180 \times H_2$$H_2 = \frac{1080}{180} = 6\, \text{hours per day}$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

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$10$ men working $6\, \text{h}$ a day can complete a work in $18\, \text{days}$. How many $\text{hours per day}$ must $15$ men work to complete the same work in $12\, \text{days}$?

A
$6$
B
$10$
C
$12$
D
$15$

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Time and Work and Wages

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Time and Work

$A$ man,a woman,and a boy can complete a job in $3, 4,$ and $12$ days respectively. How many boys must assist $1$ man and $1$ woman to complete the job in $\frac{1}{4}$ of a day?

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Five men and $2$ boys,working together,can complete four times as much work per hour as a man and a boy working together. The ratio of the work completed by a man and a boy is:

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$A$ works thrice as good as $B$ and is,therefore,able to finish a piece of work in $60 \text{ days}$ less than $B$. Find the time in which they can complete it,working together (in $\text{days}$).

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$A$ labourer can do a job in $36 \text{ hours}$. After $9 \text{ hours}$,he takes a break. What fraction of the job is yet to be done?

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$A$ can do a piece of work in $15 \text{ days}$. With the help of $A$,$B$ can do it in $6 \frac{2}{3} \text{ days}$. $B$ can do it alone in (in $\text{days}$)

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$10$ men working $6\, \text{h}$ a day can complete a work in $18\, \text{days}$. How many $\text{hours per day}$ must $15$ men work to complete the same work in $12\, \text{days}$?

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$A$ man,a woman,and a boy can complete a job in $3, 4,$ and $12$ days respectively. How many boys must assist $1$ man and $1$ woman to complete the job in $\frac{1}{4}$ of a day?

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