12 men can complete a piece of work in 4 days | vedclass

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Question

(A) $1$ day's work by a man $= \frac{1}{12 	imes 4} = \frac{1}{48}$.$1$ day's work by a woman $= \frac{1}{15 	imes 4} = \frac{1}{60}$.Part of work d

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$15$

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(A) $1$ day's work by a man $= \frac{1}{12 	imes 4} = \frac{1}{48}$.$1$ day's work by a woman $= \frac{1}{15 	imes 4} = \frac{1}{60}$.Part of work done by $6$ men in $2$ days $= (6 	imes \frac{1}{48}) 	imes 2 = \frac{12}{48} = \frac{1}{4}$.Remaining work $= 1 - \frac{1}{4} = \frac{3}{4}$.Let the number of women required to complete the remaining work in $3$ days be $x$.Then,$x 	imes (	ext{work of } 1 	ext{ woman per day}) 	imes 3 = 	ext{Remaining work}$.$x 	imes \frac{1}{60} 	imes 3 = \frac{3}{4}$.$x 	imes \frac{1}{20} = \frac{3}{4}$.$x = \frac{3}{4} 	imes 20 = 15$.Therefore,$15$ women are required.

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