A does frac{4}{5} of a work in 20 , text{days | vedclass

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(C) completes $\frac{4}{5}$ of the work in $20 \, 	ext{days}$.Therefore,the rate of work of $A$ is $\frac{4/5}{20} = \frac{1}{25}$ of the work per da

Vedclass · Accepted Answer

$37\frac{1}{2}$

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(C) completes $\frac{4}{5}$ of the work in $20 \, 	ext{days}$.Therefore,the rate of work of $A$ is $\frac{4/5}{20} = \frac{1}{25}$ of the work per day.Remaining work $= 1 - \frac{4}{5} = \frac{1}{5}$.$A$ and $B$ together finish the remaining $\frac{1}{5}$ work in $3 \, 	ext{days}$.Therefore,their combined rate of work is $\frac{1/5}{3} = \frac{1}{15}$ of the work per day.Let $x$ be the rate of work of $B$ per day.Then,$\frac{1}{25} + x = \frac{1}{15}$.$x = \frac{1}{15} - \frac{1}{25} = \frac{5 - 3}{75} = \frac{2}{75}$.Time taken by $B$ alone to complete the whole work $= \frac{1}{2/75} = \frac{75}{2} = 37\frac{1}{2} \, 	ext{days}$.

$A$ does $\frac{4}{5}$ of a work in $20 \, \text{days}$. He then calls in $B$ and they together finish the remaining work in $3 \, \text{days}$. How long would $B$ alone take to do the whole work? (in $\text{days}$)

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