5 men can complete a work in 2 days,4 women c | vedclass

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(B) The work done by $1$ man in $1$ day is $1/10$ of the total work (since $5$ men take $2$ days,$1$ man takes $5 	imes 2 = 10$ days).The work done b

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$4$

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(B) The work done by $1$ man in $1$ day is $1/10$ of the total work (since $5$ men take $2$ days,$1$ man takes $5 	imes 2 = 10$ days).The work done by $1$ woman in $1$ day is $1/12$ of the total work (since $4$ women take $3$ days,$1$ woman takes $4 	imes 3 = 12$ days).The work done by $1$ child in $1$ day is $1/15$ of the total work (since $5$ children take $3$ days,$1$ child takes $5 	imes 3 = 15$ days).Combined work done by $1$ man,$1$ woman,and $1$ child in $1$ day = $\frac{1}{10} + \frac{1}{12} + \frac{1}{15}$.Finding the common denominator $(60)$: $\frac{6+5+4}{60} = \frac{15}{60} = \frac{1}{4}$.Therefore,they can complete the work together in $4$ days.

$5$ men can complete a work in $2$ days,$4$ women can complete the same work in $3$ days and $5$ children can do it in $3$ days. $1$ man,$1$ woman and $1$ child,working together,can complete the work in (in days):

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