A and B together can complete a work in 30 da | vedclass

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(B) Let the total work be $30$ units.Since $A$ and $B$ together complete the work in $30$ days,their combined efficiency is $(A+B) = \frac{30}{30} = 1

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(B) Let the total work be $30$ units.Since $A$ and $B$ together complete the work in $30$ days,their combined efficiency is $(A+B) = \frac{30}{30} = 1$ unit/day.In $6$ days,they complete $6 	imes 1 = 6$ units of work.Remaining work $= 30 - 6 = 24$ units.This remaining $24$ units of work is completed by $B$ in $36$ days.Therefore,$B$'s efficiency $= \frac{24}{36} = \frac{2}{3}$ units/day.Since $(A+B) = 1$ unit/day,$A$'s efficiency $= 1 - \frac{2}{3} = \frac{1}{3}$ units/day.Time taken by $A$ to complete the entire work $= \frac{	ext{Total Work}}{	ext{Efficiency of } A} = \frac{30}{1/3} = 90$ days.

$A$ and $B$ together can complete a work in $30$ days. They started together but after $6$ days $A$ left the work and the work is completed by $B$ after $36$ more days. $A$ alone can complete the entire work in how many days?

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