(D) Let $1$ man's $1 \, \text{day}$ work be $M$ and $1$ woman's $1 \, \text{day}$ work be $W$.Total work = $28 \times 15 \times M = 15 \times 24 \time

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(D) Let $1$ man's $1 \, \text{day}$ work be $M$ and $1$ woman's $1 \, \text{day}$ work be $W$.Total work = $28 \times 15 \times M = 15 \times 24 \times W$.$28 M = 24 W \implies \frac{M}{W} = \frac{24}{28} = \frac{6}{7}$.Work done by $30$ men in $1 \, \text{day} = 30 M$.Work done by $18$ women in $1 \, \text{day} = 18 W$.Ratio = $\frac{30 M}{18 W} = \frac{30}{18} \times \frac{M}{W} = \frac{5}{3} \times \frac{6}{7} = \frac{5 \times 2}{7} = \frac{10}{7}$.Thus,the ratio is $10:7$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$28$ men can complete a piece of work in $15 \, \text{days}$ and $15$ women can complete the same piece of work in $24 \, \text{days}$. What is the respective ratio between the amount of work done by $30$ men in $1 \, \text{day}$ and the amount of work done by $18$ women in $1 \, \text{day}$?

A
$4:7$
B
$9:15$
C
$3:5$
D
$10:7$

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Time and Work and Wages

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Time and Work

$A, B$ and $C$ can complete a piece of work in $6, 12$ and $24$ days respectively. They altogether will complete the work in (in days):

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If $6$ men and $8$ boys can do a piece of work in $10$ days and $26$ men and $48$ boys can do the same work in $2$ days,the time taken by $15$ men and $20$ boys to do the same type of work will be (in days)

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Working efficiencies of $A$ and $B$ for completing a piece of work are in the ratio $3: 4$. The number of days taken by them to complete the work will be in the ratio:

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$A$ certain sum of money is sufficient to pay wages for $21$ days of $X$ or $28$ days of $Y$. The money is sufficient to pay the wages of both for ........ days.

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$A, B$ and $C$ can do a job in $6$ days,$12$ days and $15$ days,respectively. After $\frac{1}{8}$ of the work is completed,$C$ leaves the job. The rest of the work is done by $A$ and $B$ together. The total time taken to finish the work is (in days):

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$28$ men can complete a piece of work in $15 \, \text{days}$ and $15$ women can complete the same piece of work in $24 \, \text{days}$. What is the respective ratio between the amount of work done by $30$ men in $1 \, \text{day}$ and the amount of work done by $18$ women in $1 \, \text{day}$?

Similar Questions

$A, B$ and $C$ can complete a piece of work in $6, 12$ and $24$ days respectively. They altogether will complete the work in (in days):

If $6$ men and $8$ boys can do a piece of work in $10$ days and $26$ men and $48$ boys can do the same work in $2$ days,the time taken by $15$ men and $20$ boys to do the same type of work will be (in days)

Working efficiencies of $A$ and $B$ for completing a piece of work are in the ratio $3: 4$. The number of days taken by them to complete the work will be in the ratio:

$A$ certain sum of money is sufficient to pay wages for $21$ days of $X$ or $28$ days of $Y$. The money is sufficient to pay the wages of both for ........ days.

$A, B$ and $C$ can do a job in $6$ days,$12$ days and $15$ days,respectively. After $\frac{1}{8}$ of the work is completed,$C$ leaves the job. The rest of the work is done by $A$ and $B$ together. The total time taken to finish the work is (in days):

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