(A) Let the distance between two consecutive trees be $d$.The number of gaps between the $13^{th}$ tree and the $34^{th}$ tree is $(34 - 13) = 21$ gap

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(A) Let the distance between two consecutive trees be $d$.The number of gaps between the $13^{th}$ tree and the $34^{th}$ tree is $(34 - 13) = 21$ gaps.Distance covered in $18 \, seconds = 21d$.Speed of the car $= \frac{\text{Distance}}{\text{Time}} = \frac{21d}{18} = \frac{7d}{6} \, \text{units/second}$.The number of gaps between the $1^{st}$ tree and the $50^{th}$ tree is $(50 - 1) = 49$ gaps.Total distance to cover $= 49d$.Time taken $= \frac{\text{Total Distance}}{\text{Speed}} = \frac{49d}{7d/6} = 49 \times \frac{6}{7} = 7 \times 6 = 42 \, seconds$.

Competitive Quantitative Aptitude Time and Distances Time and Distances

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$50$ trees are standing in a line such that the distance between any two consecutive trees is the same. $A$ car takes $18 \, seconds$ to travel from the $13^{th}$ tree to the $34^{th}$ tree. How much time (in $seconds$) will it take to reach from the first tree to the $50^{th}$ tree?

A
$42$
B
$42.85$
C
$45$
D
$49$

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Time and Distances

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$50$ trees are standing in a line such that the distance between any two consecutive trees is the same. $A$ car takes $18 \, seconds$ to travel from the $13^{th}$ tree to the $34^{th}$ tree. How much time (in $seconds$) will it take to reach from the first tree to the $50^{th}$ tree?

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$A$ car travels $80 \, km$ in $2 \, hours$ and a train travels $80 \, km$ in $3 \, hours$. The ratio of the speed of the car to that of the train is

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