$(\sqrt{2209}-12) \times 5 = ?$

$A$ number consists of two digits such that the digit in the ten's place is less by $2$ than the digit in the unit's place. Three times the number added to $\frac{6}{7}$ times the number obtained by reversing the digits equals $108$. The sum of the digits in the number is:

The sum of three consecutive odd numbers is $20$ more than the first of these numbers. What is the middle number?

If $16 \%$ of $40 \%$ of a number is $8,$ the number is

If the sum of $4$ consecutive odd numbers is $184$,then find the largest number.

$18.5 \%$ of $220 + 12.4 \%$ of $680 = ?$