$\frac{1}{16}$ of $8432 + 50 \%$ of $? = 4429$

If the number $481*673$ is completely divisible by $9$,then the smallest whole number in place of $*$ will be

$A$ number when divided by $361$ gives a remainder $47$. If the same number is divided by $19$,the remainder obtained is

One-fifth of a number is equal to $\frac{5}{8}$ of another number. If $35$ is added to the first number,it becomes four times the second number. The second number is

If the digit in the unit's place of a two-digit number is halved and the digit in the ten's place is doubled,the number thus obtained is equal to the number obtained by interchanging the digits. Which of the following is definitely true?

What least number should be subtracted from $3401$ so that the result is completely divisible by $11$?