(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To solve the expression $(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64$,we can approximate the values to the nearest integers:$13.95 \approx 14$

Vedclass · Accepted Answer

$260$

Vedclass · Answer

(A) To solve the expression $(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64$,we can approximate the values to the nearest integers:$13.95 \approx 14$$15.04 \approx 15$$18.08 \approx 18$$32.64 \approx 33$Substituting these values into the expression:$(14)^{2} - (15)^{2} + (18)^{2} - 33$$= 196 - 225 + 324 - 33$$= (196 + 324) - (225 + 33)$$= 520 - 258$$= 262$Comparing this result with the given options,the closest value is $260$.

$(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64 = ?$

Similar Questions

Find the unit digit in the product $(4387)^{245} \times (621)^{72}$.

If doubling a number and adding $20$ to the result gives the same answer as multiplying the number by $8$ and taking away $4$ from the product,the number is

Two numbers are such that the ratio between them is $3:5;$ but if each is increased by $10,$ the ratio between them becomes $5:7.$ The numbers are

$\frac{3}{5}$ th of $24 \%$ of $500 - 32 = ?$

The value of $204 \times 197$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module