15 frac{2}{3} times 3 frac{1}{6} + 6 frac{1}{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,

Vedclass · Accepted Answer

$44 \frac{5}{9}$

Vedclass · Answer

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,$11 \frac{7}{18} = \frac{205}{18}$.Let the missing value be $x$.The equation becomes: $\frac{47}{3} 	imes \frac{19}{6} + \frac{19}{3} = \frac{205}{18} + x$.Calculate the product: $\frac{47 	imes 19}{3 	imes 6} = \frac{893}{18}$.Now,$\frac{893}{18} + \frac{19}{3} = \frac{205}{18} + x$.Convert $\frac{19}{3}$ to a fraction with denominator $18$: $\frac{19 	imes 6}{3 	imes 6} = \frac{114}{18}$.So,$\frac{893}{18} + \frac{114}{18} = \frac{205}{18} + x$.$\frac{1007}{18} = \frac{205}{18} + x$.$x = \frac{1007}{18} - \frac{205}{18} = \frac{802}{18}$.Simplifying $\frac{802}{18}$ by dividing by $2$: $\frac{401}{9}$.Converting $\frac{401}{9}$ to a mixed fraction: $44 \frac{5}{9}$.

$15 \frac{2}{3} \times 3 \frac{1}{6} + 6 \frac{1}{3} = 11 \frac{7}{18} + ?$

Similar Questions

If $(2+\sqrt{3}) a=(2-\sqrt{3}) b=1,$ then the value of $\frac{1}{a}+\frac{1}{b}$ is

$6 \frac{1}{7} + 15 \frac{2}{3} + 11 \frac{1}{6} = 33 \frac{1}{21} - ?$

$(8 \div 88) \times 8888088 = ?$

$13 \frac{4}{?} + 5 \frac{3}{4} \text{ of } 3 \frac{1}{5} \div 4 \frac{3}{5} = 17 \frac{4}{5}$

What will come in the place of the question mark $(?)$ in the following expression?
$59.88 \div 12.21 \times 6.35 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module