(20 div 5) div 2 + (16 div 8) times 2 + (10 d | vedclass

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Question

(A) To solve the expression $(20 \div 5) \div 2 + (16 \div 8) 	imes 2 + (10 \div 5) 	imes (3 \div 2)$,we follow the $BODMAS$ rule:Step $1$: Solve th

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(A) To solve the expression $(20 \div 5) \div 2 + (16 \div 8) 	imes 2 + (10 \div 5) 	imes (3 \div 2)$,we follow the $BODMAS$ rule:Step $1$: Solve the operations inside the parentheses:$(20 \div 5) = 4$$(16 \div 8) = 2$$(10 \div 5) = 2$$(3 \div 2) = 1.5$Step $2$: Substitute these values back into the expression:$4 \div 2 + 2 	imes 2 + 2 	imes 1.5$Step $3$: Perform division and multiplication:$2 + 4 + 3$Step $4$: Perform addition:$2 + 4 + 3 = 9$Therefore,the correct answer is $9$.

$(20 \div 5) \div 2 + (16 \div 8) \times 2 + (10 \div 5) \times (3 \div 2) = ?$

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