sqrt{5^{2} times 14 - 6 times 7 + (4)^{?}} = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given equation: $\sqrt{5^{2} 	imes 14 - 6 	imes 7 + (4)^{?}} = 18$Squaring both sides:$5^{2} 	imes 14 - 6 	imes 7 + (4)^{?} = (18)^{2}$Calcula

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Given equation: $\sqrt{5^{2} 	imes 14 - 6 	imes 7 + (4)^{?}} = 18$Squaring both sides:$5^{2} 	imes 14 - 6 	imes 7 + (4)^{?} = (18)^{2}$Calculating the values:$25 	imes 14 - 42 + (4)^{?} = 324$$350 - 42 + (4)^{?} = 324$$308 + (4)^{?} = 324$Isolating the term with the unknown:$(4)^{?} = 324 - 308$$(4)^{?} = 16$Expressing $16$ as a power of $4$:$(4)^{?} = 4^{2}$Therefore,$? = 2$. Since $2$ is not among the options $A, B, C$,the correct answer is $D$.

$\sqrt{5^{2} \times 14 - 6 \times 7 + (4)^{?}} = 18$

Similar Questions

$A$ boy was asked to multiply a given number by $\frac{8}{17}$. Instead,he divided it by $\frac{8}{17}$ and got the result $225$ more than what he should have got if he had multiplied the number by $\frac{8}{17}$. The given number was:

If $x+\frac{2}{3+\frac{4}{5+\frac{7}{6}}}=10$,then the value of $x$ is

If the numbers $\frac{3}{5}, \frac{2}{3}, \frac{3}{4}$ are given,then we can say that

What is the value of $\sqrt{729} + \sqrt{72.9} + \sqrt{7.29}$?

$3 \frac{1}{4} + 2 \frac{1}{2} - 1 \frac{5}{6} = \frac{(?)^{2}}{10} + 1 \frac{5}{12}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module