left(sqrt{3}-frac{1}{sqrt{3}}right)^{2} simpl | vedclass

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Question

(C) Using the algebraic identity $(a-b)^2 = a^2 + b^2 - 2ab$,where $a = \sqrt{3}$ and $b = \frac{1}{\sqrt{3}}$:$\left(\sqrt{3}-\frac{1}{\sqrt{3}}\righ

Vedclass · Accepted Answer

$\frac{4}{3}$

Vedclass · Answer

(C) Using the algebraic identity $(a-b)^2 = a^2 + b^2 - 2ab$,where $a = \sqrt{3}$ and $b = \frac{1}{\sqrt{3}}$:$\left(\sqrt{3}-\frac{1}{\sqrt{3}}ight)^{2} = (\sqrt{3})^2 + \left(\frac{1}{\sqrt{3}}ight)^2 - 2 	imes \sqrt{3} 	imes \frac{1}{\sqrt{3}}$$= 3 + \frac{1}{3} - 2$$= 1 + \frac{1}{3}$$= \frac{4}{3}$

$\left(\sqrt{3}-\frac{1}{\sqrt{3}}\right)^{2}$ simplifies to

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