left(frac{sqrt{625}}{11} times frac{14}{sqrt{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,evaluate the square roots in the expression:$\sqrt{625} = 25$$\sqrt{25} = 5$$\sqrt{196} = 14$Substitute these values into the expression:$\l

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) First,evaluate the square roots in the expression:$\sqrt{625} = 25$$\sqrt{25} = 5$$\sqrt{196} = 14$Substitute these values into the expression:$\left(\frac{25}{11} 	imes \frac{14}{5} 	imes \frac{11}{14}ight)$Now,cancel the common terms in the numerator and denominator:$= \left(\frac{25}{5} 	imes \frac{14}{14} 	imes \frac{11}{11}ight)$$= 5 	imes 1 	imes 1 = 5$

$\left(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}}\right)$ is equal to

Similar Questions

$\frac{\sqrt{24}+\sqrt{216}}{\sqrt{96}}=?$

If $\sqrt{1+\frac{55}{729}}=1+\frac{x}{27},$ then the value of $x$ is

$\left[\frac{3 \sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4 \sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{\sqrt{8}-\sqrt{12}}\right] = ?$

$\left(\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}+\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)$ simplifies to

If $\sqrt{15625} = 125$,then the value of $\sqrt{15625} + \sqrt{156.25} + \sqrt{1.5625}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module