sqrt{frac{0.081 times 0.484}{0.0064 times 6.2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To solve the expression $\sqrt{\frac{0.081 	imes 0.484}{0.0064 	imes 6.25}}$,we first adjust the decimal places to simplify the calculation.$\sq

Vedclass · Accepted Answer

$0.99$

Vedclass · Answer

(B) To solve the expression $\sqrt{\frac{0.081 	imes 0.484}{0.0064 	imes 6.25}}$,we first adjust the decimal places to simplify the calculation.$\sqrt{\frac{0.081 	imes 0.484}{0.0064 	imes 6.25}} = \sqrt{\frac{81 	imes 10^{-3} 	imes 484 	imes 10^{-3}}{64 	imes 10^{-4} 	imes 625 	imes 10^{-2}}}$$= \sqrt{\frac{81 	imes 484 	imes 10^{-6}}{64 	imes 625 	imes 10^{-6}}}$$= \sqrt{\frac{81 	imes 484}{64 	imes 625}}$$= \frac{\sqrt{81} 	imes \sqrt{484}}{\sqrt{64} 	imes \sqrt{625}}$$= \frac{9 	imes 22}{8 	imes 25}$$= \frac{198}{200} = 0.99$

$\sqrt{\frac{0.081 \times 0.484}{0.0064 \times 6.25}}$ is equal to

Similar Questions

$\left[\frac{3 \sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4 \sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{\sqrt{8}-\sqrt{12}}\right] = ?$

If $a=64$ and $b=289,$ then the value of $(\sqrt{\sqrt{a}+\sqrt{b}}-\sqrt{\sqrt{b}-\sqrt{a}})^{\frac{1}{2}}$ is

$\sqrt{12+\sqrt{12+\sqrt{12+\cdots}}} = ?$

If $\frac{4 \sqrt{3}+5 \sqrt{2}}{\sqrt{48}+\sqrt{18}}=a+b \sqrt{6},$ then the values of $a$ and $b$ are,respectively

Which of the following numbers,wherein some of the digits have been suppressed by symbols,can possibly be the perfect square of a $3$-digit odd number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module