$\sqrt{176+\sqrt{2401}} = ?$

In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.
$I: \frac{13}{\sqrt{x}} + \frac{9}{\sqrt{x}} = \sqrt{x}$
$II: y^4 - \frac{(13 \times 2)^{9/2}}{\sqrt{y}} = 0$

By what least number should $2450$ be multiplied so that the resulting number is a perfect square?

If $\sqrt{x} + \sqrt{441} = 0.02$,then the value of $x$ is

The square root of $\frac{9.5 \times 0.0085 \times 18.9}{0.0017 \times 1.9 \times 2.1}$ is

If $3 \sqrt{5}+\sqrt{125}=17.88$,then what will be the value of $\sqrt{80}+6 \sqrt{5}$?