[(3 sqrt{8} + sqrt{8}) times (8 sqrt{8} + 7 s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given expression: $[(3 \sqrt{8} + \sqrt{8}) 	imes (8 \sqrt{8} + 7 \sqrt{8})] - 98$Step $1$: Simplify the terms inside the parentheses.$(3 \sqrt{8

Vedclass · Accepted Answer

$382$

Vedclass · Answer

(C) Given expression: $[(3 \sqrt{8} + \sqrt{8}) 	imes (8 \sqrt{8} + 7 \sqrt{8})] - 98$Step $1$: Simplify the terms inside the parentheses.$(3 \sqrt{8} + \sqrt{8}) = 4 \sqrt{8}$$(8 \sqrt{8} + 7 \sqrt{8}) = 15 \sqrt{8}$Step $2$: Multiply the simplified terms.$(4 \sqrt{8}) 	imes (15 \sqrt{8}) = 4 	imes 15 	imes \sqrt{8} 	imes \sqrt{8}$$= 60 	imes 8 = 480$Step $3$: Subtract $98$ from the result.$480 - 98 = 382$Therefore,the correct option is $C$.

$[(3 \sqrt{8} + \sqrt{8}) \times (8 \sqrt{8} + 7 \sqrt{8})] - 98 = ?$

Similar Questions

$\frac{\sqrt{6727}}{\sqrt{7}} = ?$

$\frac{\sqrt{0.0009}}{\sqrt{0.01}} = ?$

If $a^{2}=2,$ then $(a+1)$ is equal to

If $\frac{\sqrt{256}}{\sqrt{x}}=2,$ then $x$ is equal to

The square root of $\frac{9.5 \times 0.0085 \times 18.9}{0.0017 \times 1.9 \times 2.1}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module