1, 9, 25, 49, ?, 121 | vedclass

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Question

(B) The given series is $1, 9, 25, 49, ?, 121$.These numbers can be written as squares of consecutive odd numbers:$1^2 = 1$$3^2 = 9$$5^2 = 25$$7^2 = 4

Vedclass · Accepted Answer

$81$

Vedclass · Answer

(B) The given series is $1, 9, 25, 49, ?, 121$.These numbers can be written as squares of consecutive odd numbers:$1^2 = 1$$3^2 = 9$$5^2 = 25$$7^2 = 49$$9^2 = 81$$11^2 = 121$Therefore,the missing number is $9^2 = 81$.

$101$	$323$	$545$	$767$	$989$	$111011$
$34$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$1, 9, 25, 49, ?, 121$

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