8, 9, 8, 7, 10, 9, 6, 11, 10, ?, 12 | vedclass

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Question

(A) The given series is a combination of $3$ alternating series.$1^{	ext{st}}$ series: $8, 7, 6, ?$In this series,each term is obtained by subtractin

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The given series is a combination of $3$ alternating series.$1^{	ext{st}}$ series: $8, 7, 6, ?$In this series,each term is obtained by subtracting $1$ from the previous term $(8-1=7, 7-1=6, 6-1=5)$.$2^{	ext{nd}}$ series: $9, 10, 11, 12$In this series,each term is obtained by adding $1$ to the previous term $(9+1=10, 10+1=11, 11+1=12)$.$3^{	ext{rd}}$ series: $8, 9, 10, \dots$In this series,each term is obtained by adding $1$ to the previous term $(8+1=9, 9+1=10)$.Following the pattern of the $1^{	ext{st}}$ series,the missing term is $6-1=5$.

$8$	$8$	$12$	$24$
$36$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

$8, 9, 8, 7, 10, 9, 6, 11, 10, ?, 12$

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