60121131264284571601120(A)(B)(C)(D)(E) Which | vedclass

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Question

(A) The first series follows the pattern: $1st$ term $= 60$$2nd$ term $= 60 	imes 2 + 1 = 121$$3rd$ term $= 121 + 10 = 131$$4th$ term $= 131 	imes 2

Vedclass · Accepted Answer

$524$

Vedclass · Answer

(A) The first series follows the pattern: $1st$ term $= 60$$2nd$ term $= 60 	imes 2 + 1 = 121$$3rd$ term $= 121 + 10 = 131$$4th$ term $= 131 	imes 2 + 2 = 264$$5th$ term $= 264 + 20 = 284$$6th$ term $= 284 	imes 2 + 3 = 571$$7th$ term $= 571 + 30 = 601$Applying the same logic to the second series starting with $120$:$1st$ term $= 120$$2nd$ term $(A) = 120 	imes 2 + 1 = 241$$3rd$ term $(B) = 241 + 10 = 251$$4th$ term $(C) = 251 	imes 2 + 2 = 504$$5th$ term $(D) = 504 + 20 = 524$

$60$	$121$	$131$	$264$	$284$	$571$	$601$
$120$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$600$	$360$	$360$	$450$	$600$	$800$
$1200$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$60$ $121$ $131$ $264$ $284$ $571$ $601$
$120$ $(A)$ $(B)$ $(C)$ $(D)$ $(E)$

Which of the following numbers will come in place of $(D)?$

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$60$$121$$131$$264$$284$$571$$601$$120$$(A)$$(B)$$(C)$$(D)$$(E)$ Which of the following numbers will come in place of $(D)?$