414421475582058102908(A)(B)(C)(D)(E) Which of | vedclass

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(D) The pattern of the first series is as follows:$1^{st}$ term $= 4$$2^{nd}$ term $= 4 	imes 3.5 = 14$$3^{rd}$ term $= 14 	imes 3 = 42$$4^{th}$ ter

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) The pattern of the first series is as follows:$1^{st}$ term $= 4$$2^{nd}$ term $= 4 	imes 3.5 = 14$$3^{rd}$ term $= 14 	imes 3 = 42$$4^{th}$ term $= 42 	imes 3.5 = 147$$5^{th}$ term $= 147 	imes 4 = 588$$6^{th}$ term $= 588 	imes 3.5 = 2058$$7^{th}$ term $= 2058 	imes 5 = 10290$Applying the same logic to the second series starting with $8$:$1^{st}$ term $= 8$$2^{nd}$ term $(A) = 8 	imes 3.5 = 28$$3^{rd}$ term $(B) = 28 	imes 3 = 84$$4^{th}$ term $(C) = 84 	imes 3.5 = 294$Since $294$ is not among the given options,the correct answer is 'None of these'.

$4$	$14$	$42$	$147$	$558$	$2058$	$10290$
$8$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$4$ $14$ $42$ $147$ $558$ $2058$ $10290$
$8$ $(A)$ $(B)$ $(C)$ $(D)$ $(E)$

Which of the following numbers will come in place of $(C)?$

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$4$$14$$42$$147$$558$$2058$$10290$$8$$(A)$$(B)$$(C)$$(D)$$(E)$ Which of the following numbers will come in place of $(C)?$