Find the missing number in the series: 4000, | vedclass

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Question

(B) The pattern of the series is based on the difference between consecutive terms being halved.$4000 - 2008 = 1992$; $1992 / 2 = 996$$2008 - 1012 = 9

Vedclass · Accepted Answer

$514$

Vedclass · Answer

(B) The pattern of the series is based on the difference between consecutive terms being halved.$4000 - 2008 = 1992$; $1992 / 2 = 996$$2008 - 1012 = 996$; $996 / 2 = 498$$1012 - x = 498 \implies x = 1012 - 498 = 514$$514 - 265 = 249$; $249 / 2 = 124.5$$265 - 140.5 = 124.5$; $124.5 / 2 = 62.25$$140.5 - 78.25 = 62.25$; $62.25 / 2 = 31.125$Thus,the missing number is $514$.

$13$	$14$	$5$	$18$	$0.5$
$19$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$1$	$9$	$65$	$393$
$2$	$(A)$	$(B)$	$(C)$

Find the missing number in the series: $4000, 2008, 1012, ?, 265, 140.5, 78.25$.

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$1$ $9$ $65$ $393$
$2$ $(A)$ $(B)$ $(C)$

Which of the following numbers will come in place of $(C)$?

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