$CH_2 = CH_2 \xrightarrow[KOH / H_2O]{KMnO_4} X$. The product $X$ in the above reaction is:

In which of the following species,addition of $H^{+}$ will be faster in comparison to other three species?

What is the major product of the following reaction?

$2$-Butanol $\xrightarrow[\Delta]{H^{+}}$ Products. If all products formed in the above reaction undergo reaction with $Br_2(CCl_4)$ individually,then the number of products formed will be:

Cyclohexene on reaction with $OsO_4$ followed by reaction with $NaHSO_3$ gives

Reaction of one molecule of $HBr$ with one molecule of $1,3-$butadiene at $40\,^{\circ}C$ gives predominantly