$3$-Phenylpropene on reaction with $HBr$ gives (as a major product)
- A$C_6H_5CH_2CH(Br)CH_3$
- B$C_6H_5CH(Br)CH_2CH_3$
- C$C_6H_5CH_2CH_2CH_2Br$
- D$C_6H_5CH(Br)CH = CH_2$
Explore More
Similar Questions
Identify the reagent $A$ in the following conversion.
Alkyl halide $\xrightarrow{A}$ Alkyl nitrite
Alkyl halide $\xrightarrow{A}$ Alkyl nitrite
Which of the following is the correct order of boiling points for alkyl halides?
Easy
View Solution$A$ halogen compound $X$ $(C_4 H_9 Br)$ on hydrolysis gives an alcohol $Y$. The alcohol $Y$ undergoes dehydration with $20 \% H_3 PO_4$ at $358 \ K$. What is $X$?
Match List-$I$ with List-$II$.
$1$-Bromopropane is reacted with reagents in List-$I$ to give products in List-$II$.
List-$I$ (Reagent) List-$II$ (Product) $A$. $KOH$ (alc) $I$. Nitrile $B$. $KCN$ (alc) $II$. Ester $C$. $AgNO_2$ $III$. Alkene $D$. $CH_3COOAg$ $IV$. Nitroalkane
$1$-Bromopropane is reacted with reagents in List-$I$ to give products in List-$II$.
| List-$I$ (Reagent) | List-$II$ (Product) |
|---|---|
| $A$. $KOH$ (alc) | $I$. Nitrile |
| $B$. $KCN$ (alc) | $II$. Ester |
| $C$. $AgNO_2$ | $III$. Alkene |
| $D$. $CH_3COOAg$ | $IV$. Nitroalkane |
The reactivity order of the following molecules towards $S_N1$ reaction is:
$(I)$ Allyl chloride
$(II)$ Chlorobenzene
$(III)$ Ethyl chloride
$(I)$ Allyl chloride
$(II)$ Chlorobenzene
$(III)$ Ethyl chloride
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo