KMnO_4 will oxidise acetylene to | vedclass

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Question

(C) Acetylene $(HC \equiv CH)$ is oxidized by $KMnO_4$ to form oxalic acid $(HOOC-COOH)$.The reaction is: $HC \equiv CH + 4[O] \xrightarrow{KMnO_4} HO

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Oxalic acid

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(C) Acetylene $(HC \equiv CH)$ is oxidized by $KMnO_4$ to form oxalic acid $(HOOC-COOH)$.The reaction is: $HC \equiv CH + 4[O] \xrightarrow{KMnO_4} HOOC-COOH$.

$KMnO_4$ will oxidise acetylene to

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